What is the derivative of 2sec(x) 2 sec(x) with respect to X?

Since 2 2 is constant with respect to x x, the derivative of 2sec(x) 2 sec ( x) with respect to x x is 2 d dx [sec(x)] 2 d d x [ sec ( x)]. The derivative of sec(x) sec ( x) with respect to x x is sec(x)tan(x) sec ( x) tan ( x).

What is d/dx(sec2x)?

What is d/dx(sec2x)? Let y = sec^2 x. Let sec x = t. Then. y = t^2. This implies dy/dt = 2t = 2 sec x t = sec x implies dt/dx = sec x.tan x. So. dy/dx = (dy/dt)× (dt/dx) = 2sec x . sec x. tan x = 2 sec^2 x .tan x. ...

What is the minimum value of cosec 2X+SEC 2x?

Minimum value of cosec 2x+sec 2x is 4. So, minimum value of y is 9. Was this answer helpful? 1. Max. value of 3sinx+4cosx a.24 2. Min. positive value of sinx+cosecx b.5 3. Min. value of 9sin 2x+16cosec 2x c.2 4. Max. value of sin 4x+cos 4x d.1

What is the value of Sec^{2}(x)?

trigonometric-equation-calculator sec^{2}(x) = 2secx en Related Symbolab blog posts I know what you did last summer…Trigonometric Proofs